awk遍历目录下所有文件统计相应内容

#!/bin/bash
function getdir(){
    for element in `ls $1`
    do
        dir_or_file=$1"/"$element
        if [ -d $dir_or_file ]
        then
            getdir $dir_or_file
        else
            # 匹配 '\apps\' 
	        awk  -v thisfile="$dir_or_file" '{if($0 ~ "\\\\apps\\\\"){print thisfile, NR, $0}}'  $dir_or_file
        fi
    done
}
root_dir="/Users/mfw/Documents/work/pay"
getdir $root_dir